12t^2-t-63=0

Solution for 12t^2-t-63=0 equation:

12t^2-t-63=0

We add all the numbers together, and all the variables

12t^2-1t-63=0

a = 12; b = -1; c = -63;
Δ = b2-4ac
Δ = -12-4·12·(-63)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-55}{2*12}=\frac{-54}{24}
=-2+1/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+55}{2*12}=\frac{56}{24}
=2+1/3
$